What are the solutions to the equation 9x^2-2x-7=0 ?

The solutions to the equation 9x^2-2x-7=0 are x=1,x=-7/9

Find the zeros of 9x^2-2x-7=0

The zeros of 9x^2-2x-7=0 are x=1,x=-7/9

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9 x^{2} - 2 x - 7 = 0

x = 1, x = - \frac{7}{9}

Decimal Notation

x = 1, x = - 0.77777 \dots

Solution steps

9 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 7 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 7) = 16

x_{1, 2} = \frac{- ( - 2 ) \pm 16}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 16}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 16}{2 \cdot 9}

x = \frac{- ( - 2 ) + 16}{2 \cdot 9} : 1

x = \frac{- ( - 2 ) - 16}{2 \cdot 9} : - \frac{7}{9}

The solutions to the quadratic equation are:

x = 1, x = - \frac{7}{9}

x, 5 x^{2} - 3 x - 2 = 0

x, x^{2} - 2 x + y^{2} - 4 y - z^{2} + 6 z = 0

5 x^{2} = 14

c^{2} - 2 c + 0.1 = 0

w, 36 + 96 = 5.625 w^{2}

What are the solutions to the equation 9x^2-2x-7=0 ?
The solutions to the equation 9x^2-2x-7=0 are x=1,x=-7/9
Find the zeros of 9x^2-2x-7=0
The zeros of 9x^2-2x-7=0 are x=1,x=-7/9