What are the solutions to the equation solvefor x,y=x^2-1 ?

The solutions to the equation solvefor x,y=x^2-1 are x=sqrt(y+1),x=-sqrt(y+1)

Find the zeros of solvefor x,y=x^2-1

The zeros of solvefor x,y=x^2-1 are x=sqrt(y+1),x=-sqrt(y+1)

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solve for

x, y = x^{2} - 1

x = y + 1, x = - y + 1

Solution steps

y = x^{2} - 1

Switch sides

x^{2} - 1 = y

Move

1

to the right side

x^{2} = y + 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y + 1, x = - y + 1

x, y = x^{2} - 2

x (x + 7) = 690

2 x (3 x + 5) = - 1 + 4 x

\frac{1}{2} x^{2} - 4 x + 3

x^{2} + a^{2} x^{2} - 4 x a^{2} + 4 a^{2} = 1

What are the solutions to the equation solvefor x,y=x^2-1 ?
The solutions to the equation solvefor x,y=x^2-1 are x=sqrt(y+1),x=-sqrt(y+1)
Find the zeros of solvefor x,y=x^2-1
The zeros of solvefor x,y=x^2-1 are x=sqrt(y+1),x=-sqrt(y+1)