What are the solutions to the equation 9x^2-2x-2=0 ?

The solutions to the equation 9x^2-2x-2=0 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9

Find the zeros of 9x^2-2x-2=0

The zeros of 9x^2-2x-2=0 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 2 x - 2 = 0

x = \frac{1 + 19}{9}, x = \frac{1 - 19}{9}

Decimal Notation

x = 0.59543 \dots, x = - 0.37321 \dots

Solution steps

9 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 2)^{2} - 4 \cdot 9 (- 2) = 219

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19}{2 \cdot 9}, x_{2} = \frac{- ( - 2 ) - 2 19}{2 \cdot 9}

x = \frac{- ( - 2 ) + 2 19}{2 \cdot 9} : \frac{1 + 19}{9}

x = \frac{- ( - 2 ) - 2 19}{2 \cdot 9} : \frac{1 - 19}{9}

The solutions to the quadratic equation are:

x = \frac{1 + 19}{9}, x = \frac{1 - 19}{9}

x^{2} + 3 x - 550 = 0

\frac{1}{14400} (3 x^{2} - 460 x + 15600) = 0

0 = 6 (x - 1) (x + 2)

a, - 6 a^{2} + 12 - 12 ab - 6 b = 0

x^{2} = 2 1^{2} + 2 0^{2}

What are the solutions to the equation 9x^2-2x-2=0 ?
The solutions to the equation 9x^2-2x-2=0 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9
Find the zeros of 9x^2-2x-2=0
The zeros of 9x^2-2x-2=0 are x=(1+sqrt(19))/9 ,x=(1-sqrt(19))/9