What are the solutions to the equation factor 2x^2-5x-7=0 ?

The solutions to the equation factor 2x^2-5x-7=0 are x=-1,x= 7/2

Find the zeros of factor 2x^2-5x-7=0

The zeros of factor 2x^2-5x-7=0 are x=-1,x= 7/2

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2 x^{2} - 5 x - 7 = 0

x = - 1, x = \frac{7}{2}

Decimal Notation

x = - 1, x = 3.5

Solution steps

2 x^{2} - 5 x - 7 = 0

Factor

2 x^{2} - 5 x - 7 : (x + 1) (2 x - 7)

(x + 1) (2 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 7 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 7 = 0 : x = \frac{7}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{7}{2}

(- x - 1)^{2} = 0

x, f (x yz) = x^{2} + y^{2} + z^{2}

\frac{1}{2} x^{2} + 5 x = - 17

y^{2} - 9 y - 18 = 0

x^{2} - 83 x + 169 = 0

What are the solutions to the equation factor 2x^2-5x-7=0 ?
The solutions to the equation factor 2x^2-5x-7=0 are x=-1,x= 7/2
Find the zeros of factor 2x^2-5x-7=0
The zeros of factor 2x^2-5x-7=0 are x=-1,x= 7/2