What are the solutions to the equation 2x^1-x^2+3=1 ?

The solutions to the equation 2x^1-x^2+3=1 are x=1-sqrt(3),x=1+sqrt(3)

Find the zeros of 2x^1-x^2+3=1

The zeros of 2x^1-x^2+3=1 are x=1-sqrt(3),x=1+sqrt(3)

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2 x^{1} - x^{2} + 3 = 1

x = 1 - 3, x = 1 + 3

Decimal Notation

x = - 0.73205 \dots, x = 2.73205 \dots

Solution steps

2 x^{1} - x^{2} + 3 = 1

Refine

2 x - x^{2} + 3 = 1

Move

1

to the left side

- x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 2 = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 3}{2 ( - 1 )}

x = \frac{- 2 + 2 3}{2 ( - 1 )} : 1 - 3

x = \frac{- 2 - 2 3}{2 ( - 1 )} : 1 + 3

The solutions to the quadratic equation are:

x = 1 - 3, x = 1 + 3

6 x^{2} - 4 x = 0

4^{2} + x^{2} = 1 1^{2}

3 y^{2} - 7 y = 3

5 n^{2} + 8 = 4

x^{2} + 0.47 x - 0.752 = 0

What are the solutions to the equation 2x^1-x^2+3=1 ?
The solutions to the equation 2x^1-x^2+3=1 are x=1-sqrt(3),x=1+sqrt(3)
Find the zeros of 2x^1-x^2+3=1
The zeros of 2x^1-x^2+3=1 are x=1-sqrt(3),x=1+sqrt(3)