What are the solutions to the equation 5n^2+8=4 ?

The solutions to the equation 5n^2+8=4 are n= 2/(sqrt(5))i,n=-2/(sqrt(5))i

Find the zeros of 5n^2+8=4

The zeros of 5n^2+8=4 are n= 2/(sqrt(5))i,n=-2/(sqrt(5))i

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5 n^{2} + 8 = 4

n = \frac{2}{5} i, n = - \frac{2}{5} i

Solution steps

5 n^{2} + 8 = 4

Move

8

to the right side

5 n^{2} = - 4

Divide both sides by

5

n^{2} = - \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - \frac{4}{5}, n = - - \frac{4}{5}

- \frac{4}{5} = \frac{2}{5} i

- - \frac{4}{5} = - \frac{2}{5} i

n = \frac{2}{5} i, n = - \frac{2}{5} i

x^{2} + 0.47 x - 0.752 = 0

- x^{2} + 3 x + 28 = 0

6 x^{2} + 5 x - 4 = 0

x (x - 3) + 1 = 0

x, f (x + 3) = 4 x^{2} + 3 x - 4

What are the solutions to the equation 5n^2+8=4 ?
The solutions to the equation 5n^2+8=4 are n= 2/(sqrt(5))i,n=-2/(sqrt(5))i
Find the zeros of 5n^2+8=4
The zeros of 5n^2+8=4 are n= 2/(sqrt(5))i,n=-2/(sqrt(5))i