What are the solutions to the equation 3y^2-7y=3 ?

The solutions to the equation 3y^2-7y=3 are y=(7+sqrt(85))/6 ,y=(7-sqrt(85))/6

Find the zeros of 3y^2-7y=3

The zeros of 3y^2-7y=3 are y=(7+sqrt(85))/6 ,y=(7-sqrt(85))/6

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3 y^{2} - 7 y = 3

y = \frac{7 + 85}{6}, y = \frac{7 - 85}{6}

Decimal Notation

y = 2.70325 \dots, y = - 0.36992 \dots

Solution steps

3 y^{2} - 7 y = 3

Move

3

to the left side

3 y^{2} - 7 y - 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 3) = 85

y_{1, 2} = \frac{- ( - 7 ) \pm 85}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 85}{2 \cdot 3}, y_{2} = \frac{- ( - 7 ) - 85}{2 \cdot 3}

y = \frac{- ( - 7 ) + 85}{2 \cdot 3} : \frac{7 + 85}{6}

y = \frac{- ( - 7 ) - 85}{2 \cdot 3} : \frac{7 - 85}{6}

The solutions to the quadratic equation are:

y = \frac{7 + 85}{6}, y = \frac{7 - 85}{6}

5 n^{2} + 8 = 4

x^{2} + 0.47 x - 0.752 = 0

- x^{2} + 3 x + 28 = 0

6 x^{2} + 5 x - 4 = 0

x (x - 3) + 1 = 0

What are the solutions to the equation 3y^2-7y=3 ?
The solutions to the equation 3y^2-7y=3 are y=(7+sqrt(85))/6 ,y=(7-sqrt(85))/6
Find the zeros of 3y^2-7y=3
The zeros of 3y^2-7y=3 are y=(7+sqrt(85))/6 ,y=(7-sqrt(85))/6