What are the solutions to the equation 56=-x^2+15x ?

The solutions to the equation 56=-x^2+15x are x=7,x=8

Find the zeros of 56=-x^2+15x

The zeros of 56=-x^2+15x are x=7,x=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

56 = - x^{2} + 15 x

x = 7, x = 8

Solution steps

56 = - x^{2} + 15 x

Switch sides

- x^{2} + 15 x = 56

Move

56

to the left side

- x^{2} + 15 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 1 ) ( - 56 )}{2 ( - 1 )}

1 5^{2} - 4 (- 1) (- 56) = 1

x_{1, 2} = \frac{- 15 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 15 + 1}{2 ( - 1 )}, x_{2} = \frac{- 15 - 1}{2 ( - 1 )}

x = \frac{- 15 + 1}{2 ( - 1 )} : 7

x = \frac{- 15 - 1}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 7, x = 8

(x - 1) (5 x + 1) = 216

- 0.5 x^{2} - 30 x + 350 = 0

2.5 x^{2} = 5 x + 50 - 8487.05 - 848.705 x

x^{2} - 39 = - 2 x + 9

3 x^{2} + 5 x + 2

What are the solutions to the equation 56=-x^2+15x ?
The solutions to the equation 56=-x^2+15x are x=7,x=8
Find the zeros of 56=-x^2+15x
The zeros of 56=-x^2+15x are x=7,x=8