What are the solutions to the equation 16+x^2=0 ?

The solutions to the equation 16+x^2=0 are x=4i,x=-4i

Find the zeros of 16+x^2=0

The zeros of 16+x^2=0 are x=4i,x=-4i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 + x^{2} = 0

x = 4 i, x = - 4 i

Solution steps

16 + x^{2} = 0

Move

16

to the right side

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

9 p^{2} - 27 p + 2 = 0

1 2^{2} = 9^{2} + b^{2}

x^{2} - 49 = 0

9 w^{2} + 25 = 30 w

x^{2} - 8 x = 84

What are the solutions to the equation 16+x^2=0 ?
The solutions to the equation 16+x^2=0 are x=4i,x=-4i
Find the zeros of 16+x^2=0
The zeros of 16+x^2=0 are x=4i,x=-4i