What are the solutions to the equation 6x^2+5x=2 ?

The solutions to the equation 6x^2+5x=2 are x=(-5+sqrt(73))/(12),x=(-5-sqrt(73))/(12)

Find the zeros of 6x^2+5x=2

The zeros of 6x^2+5x=2 are x=(-5+sqrt(73))/(12),x=(-5-sqrt(73))/(12)

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6 x^{2} + 5 x = 2

x = \frac{- 5 + 73}{12}, x = \frac{- 5 - 73}{12}

Decimal Notation

x = 0.29533 \dots, x = - 1.12866 \dots

Solution steps

6 x^{2} + 5 x = 2

Move

2

to the left side

6 x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 2) = 73

x_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 73}{2 \cdot 6}, x_{2} = \frac{- 5 - 73}{2 \cdot 6}

x = \frac{- 5 + 73}{2 \cdot 6} : \frac{- 5 + 73}{12}

x = \frac{- 5 - 73}{2 \cdot 6} : \frac{- 5 - 73}{12}

The solutions to the quadratic equation are:

x = \frac{- 5 + 73}{12}, x = \frac{- 5 - 73}{12}

x^{2} + 3 x - 30 = - 6 + x

24.1 = 4.9 t^{2}

x^{2} + \frac{5}{100} x + \frac{4}{10000} = 0

x^{2} + 9 x + 9 + 8 = 0

5 y^{2} + 10 y + 4 = 0

What are the solutions to the equation 6x^2+5x=2 ?
The solutions to the equation 6x^2+5x=2 are x=(-5+sqrt(73))/(12),x=(-5-sqrt(73))/(12)
Find the zeros of 6x^2+5x=2
The zeros of 6x^2+5x=2 are x=(-5+sqrt(73))/(12),x=(-5-sqrt(73))/(12)