What are the solutions to the equation x^2-30x=-125 ?

The solutions to the equation x^2-30x=-125 are x=25,x=5

Find the zeros of x^2-30x=-125

The zeros of x^2-30x=-125 are x=25,x=5

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x^{2} - 30 x = - 125

x = 25, x = 5

Solution steps

x^{2} - 30 x = - 125

Move

125

to the left side

x^{2} - 30 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 1 \cdot 125}{2 \cdot 1}

(- 30)^{2} - 4 \cdot 1 \cdot 125 = 20

x_{1, 2} = \frac{- ( - 30 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 30 ) - 20}{2 \cdot 1}

x = \frac{- ( - 30 ) + 20}{2 \cdot 1} : 25

x = \frac{- ( - 30 ) - 20}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 25, x = 5

- k^{2} - k + 6 = 0

2 0^{2} + 6^{2} = c^{2}

5 a^{2} + 2 a - 33 = 0

a^{2} + 3 a + 1 = 0

b^{2} + 8 b + 7 = 0

What are the solutions to the equation x^2-30x=-125 ?
The solutions to the equation x^2-30x=-125 are x=25,x=5
Find the zeros of x^2-30x=-125
The zeros of x^2-30x=-125 are x=25,x=5