What are the solutions to the equation 20^2+6^2=c^2 ?

The solutions to the equation 20^2+6^2=c^2 are c=2sqrt(109),c=-2sqrt(109)

Find the zeros of 20^2+6^2=c^2

The zeros of 20^2+6^2=c^2 are c=2sqrt(109),c=-2sqrt(109)

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2 0^{2} + 6^{2} = c^{2}

c = 2109, c = - 2109

Decimal Notation

c = 20.88061 \dots, c = - 20.88061 \dots

Solution steps

2 0^{2} + 6^{2} = c^{2}

Switch sides

c^{2} = 2 0^{2} + 6^{2}

Simplify

2 0^{2} + 6^{2} : 436

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 436, c = - 436

436 = 2109

- 436 = - 2109

c = 2109, c = - 2109

5 a^{2} + 2 a - 33 = 0

a^{2} + 3 a + 1 = 0

b^{2} + 8 b + 7 = 0

(1) = x^{2}

2 r^{2} + 12 r + 10 = 0

What are the solutions to the equation 20^2+6^2=c^2 ?
The solutions to the equation 20^2+6^2=c^2 are c=2sqrt(109),c=-2sqrt(109)
Find the zeros of 20^2+6^2=c^2
The zeros of 20^2+6^2=c^2 are c=2sqrt(109),c=-2sqrt(109)