What are the solutions to the equation x^2+(4/5)^2=1 ?

The solutions to the equation x^2+(4/5)^2=1 are x= 3/5 ,x=-3/5

Find the zeros of x^2+(4/5)^2=1

The zeros of x^2+(4/5)^2=1 are x= 3/5 ,x=-3/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + (\frac{4}{5})^{2} = 1

x = \frac{3}{5}, x = - \frac{3}{5}

Decimal Notation

x = 0.6, x = - 0.6

Solution steps

x^{2} + (\frac{4}{5})^{2} = 1

Expand

x^{2} + (\frac{4}{5})^{2} : x^{2} + \frac{16}{25}

x^{2} + \frac{16}{25} = 1

Move

\frac{16}{25}

to the right side

x^{2} = 1 - \frac{16}{25}

Simplify

1 - \frac{16}{25} : \frac{9}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{25}, x = - \frac{9}{25}

\frac{9}{25} = \frac{3}{5}

- \frac{9}{25} = - \frac{3}{5}

x = \frac{3}{5}, x = - \frac{3}{5}

0 = y^{2} - 4 y

(\frac{3}{2} x - \frac{1}{2})^{2} - 0.8 (1 - x) = 0

(200 + 20 x) (40 - 2 x) = 9000

t = \frac{1}{2} \cdot (- 9.81) \cdot t^{2} + 20 \cdot t + 5

- 4 d^{2} - d + 3 = 0

What are the solutions to the equation x^2+(4/5)^2=1 ?
The solutions to the equation x^2+(4/5)^2=1 are x= 3/5 ,x=-3/5
Find the zeros of x^2+(4/5)^2=1
The zeros of x^2+(4/5)^2=1 are x= 3/5 ,x=-3/5