What are the solutions to the equation -5w^2+9w+1=-6w^2 ?

The solutions to the equation -5w^2+9w+1=-6w^2 are w=(-9+sqrt(77))/2 ,w=(-9-sqrt(77))/2

Find the zeros of -5w^2+9w+1=-6w^2

The zeros of -5w^2+9w+1=-6w^2 are w=(-9+sqrt(77))/2 ,w=(-9-sqrt(77))/2

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- 5 w^{2} + 9 w + 1 = - 6 w^{2}

w = \frac{- 9 + 77}{2}, w = \frac{- 9 - 77}{2}

Decimal Notation

w = - 0.11251 \dots, w = - 8.88748 \dots

Solution steps

- 5 w^{2} + 9 w + 1 = - 6 w^{2}

Move

6 w^{2}

to the left side

w^{2} + 9 w + 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 1 = 77

w_{1, 2} = \frac{- 9 \pm 77}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 9 + 77}{2 \cdot 1}, w_{2} = \frac{- 9 - 77}{2 \cdot 1}

w = \frac{- 9 + 77}{2 \cdot 1} : \frac{- 9 + 77}{2}

w = \frac{- 9 - 77}{2 \cdot 1} : \frac{- 9 - 77}{2}

The solutions to the quadratic equation are:

w = \frac{- 9 + 77}{2}, w = \frac{- 9 - 77}{2}

(x - 1)^{2} = x - 3 (x - 3 + 5)

- 4 x^{2} + 3 x + 7 = 0

x^{2} = 5 \cdot 15

x^{2} + 6 x - 2 = 0

x, x^{2} + 4 x y - 4 y^{2} - 3 x + 4 y - 10 = 0

What are the solutions to the equation -5w^2+9w+1=-6w^2 ?
The solutions to the equation -5w^2+9w+1=-6w^2 are w=(-9+sqrt(77))/2 ,w=(-9-sqrt(77))/2
Find the zeros of -5w^2+9w+1=-6w^2
The zeros of -5w^2+9w+1=-6w^2 are w=(-9+sqrt(77))/2 ,w=(-9-sqrt(77))/2