What are the solutions to the equation 10x^2+20x+5=0 ?

The solutions to the equation 10x^2+20x+5=0 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))

Find the zeros of 10x^2+20x+5=0

The zeros of 10x^2+20x+5=0 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))

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10 x^{2} + 20 x + 5 = 0

x = \frac{- 2 + 2}{2}, x = - \frac{2 + 1}{2}

Decimal Notation

x = - 0.29289 \dots, x = - 1.70710 \dots

Solution steps

10 x^{2} + 20 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 \cdot 5}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 \cdot 5 = 102

x_{1, 2} = \frac{- 20 \pm 10 2}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 20 + 10 2}{2 \cdot 10}, x_{2} = \frac{- 20 - 10 2}{2 \cdot 10}

x = \frac{- 20 + 10 2}{2 \cdot 10} : \frac{- 2 + 2}{2}

x = \frac{- 20 - 10 2}{2 \cdot 10} : - \frac{2 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 2}{2}, x = - \frac{2 + 1}{2}

- 2 p^{2} + 3 p + 6 = 0

- 9 x^{2} + x - 8 = 0

(x - 21)^{2} = 484

X^{3} = (X - 300)^{3} + 100

b^{2} - b - 12 = 0

What are the solutions to the equation 10x^2+20x+5=0 ?
The solutions to the equation 10x^2+20x+5=0 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))
Find the zeros of 10x^2+20x+5=0
The zeros of 10x^2+20x+5=0 are x=(-2+sqrt(2))/2 ,x=-(sqrt(2)+1)/(sqrt(2))