What are the solutions to the equation n^2-3n-418=0 ?

The solutions to the equation n^2-3n-418=0 are n=22,n=-19

Find the zeros of n^2-3n-418=0

The zeros of n^2-3n-418=0 are n=22,n=-19

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n^{2} - 3 n - 418 = 0

n = 22, n = - 19

Solution steps

n^{2} - 3 n - 418 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 418 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 418) = 41

n_{1, 2} = \frac{- ( - 3 ) \pm 41}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 41}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 41}{2 \cdot 1}

n = \frac{- ( - 3 ) + 41}{2 \cdot 1} : 22

n = \frac{- ( - 3 ) - 41}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

n = 22, n = - 19

0 = 8 x - 2 x^{2}

(x - 5)^{2} - 25 = 0

2 x^{2} = 28 - 10 x

x, 2 x^{2} - 7 x + 5 = 0

4 + q = 16 - q^{2}

What are the solutions to the equation n^2-3n-418=0 ?
The solutions to the equation n^2-3n-418=0 are n=22,n=-19
Find the zeros of n^2-3n-418=0
The zeros of n^2-3n-418=0 are n=22,n=-19