What are the solutions to the equation solvefor B,rs=ro+B/s (ro-rB)(1-Tc) ?

The solutions to the equation solvefor B,rs=ro+B/s (ro-rB)(1-Tc) are

Find the zeros of solvefor B,rs=ro+B/s (ro-rB)(1-Tc)

The zeros of solvefor B,rs=ro+B/s (ro-rB)(1-Tc) are

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solve for

B, rs = ro + \frac{B}{s} (ro - r B) (1 - T c)

B = \frac{- ro + ro T c + ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}, B = \frac{- ro + ro T c - ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}; - r + r T c \neq = 0

Solution steps

rs = ro + \frac{B}{s} (ro - r B) (1 - T c)

Multiply both sides by

s

r s^{2} = rso + B (ro - B r) (1 - T c); s \neq = 0

Expand

rso + B (ro - B r) (1 - T c) : rso + B ro - B ro T c - B^{2} r + B^{2} r T c

r s^{2} = rso + B ro - B ro T c - B^{2} r + B^{2} r T c; s \neq = 0

Switch sides

rso + B ro - B ro T c - B^{2} r + B^{2} r T c = r s^{2}; s \neq = 0

Move

r s^{2}

to the left side

rso + B ro - B ro T c - B^{2} r + B^{2} r T c - r s^{2} = 0; s \neq = 0

Write in the standard form

a x^{2} + b x + c = 0

(- r + r T c) B^{2} + (ro - ro T c) B + rso - r s^{2} = 0; s \neq = 0

Solve with the quadratic formula

B_{1, 2} = \frac{- ( ro - ro T c ) \pm ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}

B = \frac{- ( ro - ro T c ) + ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )} : \frac{- ro + ro T c + ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}

B = \frac{- ( ro - ro T c ) - ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )} : \frac{- ro + ro T c - ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}

The solutions to the quadratic equation are:

B = \frac{- ro + ro T c + ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}, B = \frac{- ro + ro T c - ( ro - ro T c ) ^{2} - 4 ( - r + r T c ) ( rso - r s ^{2} )}{2 ( - r + r T c )}; - r + r T c \neq = 0

2 \cdot ((30 - 2 x) x + (20 - 2 x) x) = 200

x^{2} - 18 x = 7

x^{2} - 18 x = 6

y, y^{2} = x (3 - x)^{2}

- 5 (x - 3) + 2 = \frac{1}{2} x (x - 2)

What are the solutions to the equation solvefor B,rs=ro+B/s (ro-rB)(1-Tc) ?
The solutions to the equation solvefor B,rs=ro+B/s (ro-rB)(1-Tc) are
Find the zeros of solvefor B,rs=ro+B/s (ro-rB)(1-Tc)
The zeros of solvefor B,rs=ro+B/s (ro-rB)(1-Tc) are