What are the solutions to the equation (2x-1)^2-4=0 ?

The solutions to the equation (2x-1)^2-4=0 are x= 3/2 ,x=-1/2

Find the zeros of (2x-1)^2-4=0

The zeros of (2x-1)^2-4=0 are x= 3/2 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 1)^{2} - 4 = 0

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal

x = 1.5, x = - 0.5

Solution steps

(2 x - 1)^{2} - 4 = 0

Move

4

to the right side

(2 x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 4 : x = \frac{3}{2}

Solve

2 x - 1 = - 4 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

4 x^{2} - 29 x - 24 = 0

x^{2} + (4 + x)^{2} = (8 + x)^{2}

2 x^{2} - 16 x + 24 = 0

2 x^{2} + 20 x - 22 = 0

2 x^{2} - 28 x + 102

What are the solutions to the equation (2x-1)^2-4=0 ?
The solutions to the equation (2x-1)^2-4=0 are x= 3/2 ,x=-1/2
Find the zeros of (2x-1)^2-4=0
The zeros of (2x-1)^2-4=0 are x= 3/2 ,x=-1/2