What are the solutions to the equation 4x^2-29x-24=0 ?

The solutions to the equation 4x^2-29x-24=0 are x=8,x=-3/4

Find the zeros of 4x^2-29x-24=0

The zeros of 4x^2-29x-24=0 are x=8,x=-3/4

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4 x^{2} - 29 x - 24 = 0

x = 8, x = - \frac{3}{4}

Decimal Notation

x = 8, x = - 0.75

Solution steps

4 x^{2} - 29 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

(- 29)^{2} - 4 \cdot 4 (- 24) = 35

x_{1, 2} = \frac{- ( - 29 ) \pm 35}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 35}{2 \cdot 4}, x_{2} = \frac{- ( - 29 ) - 35}{2 \cdot 4}

x = \frac{- ( - 29 ) + 35}{2 \cdot 4} : 8

x = \frac{- ( - 29 ) - 35}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 8, x = - \frac{3}{4}

x^{2} + (4 + x)^{2} = (8 + x)^{2}

2 x^{2} - 16 x + 24 = 0

2 x^{2} + 20 x - 22 = 0

2 x^{2} - 28 x + 102

x, x^{2} + 2 x - 24 = 0

What are the solutions to the equation 4x^2-29x-24=0 ?
The solutions to the equation 4x^2-29x-24=0 are x=8,x=-3/4
Find the zeros of 4x^2-29x-24=0
The zeros of 4x^2-29x-24=0 are x=8,x=-3/4