What are the solutions to the equation completesquare 2x^2-28x+102 ?

The solutions to the equation completesquare 2x^2-28x+102 are 2(x-7)^2+4

Find the zeros of completesquare 2x^2-28x+102

The zeros of completesquare 2x^2-28x+102 are 2(x-7)^2+4

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complete the square

2 x^{2} - 28 x + 102

2 (x - 7)^{2} + 4

Solution steps

2 x^{2} - 28 x + 102

Write

2 x^{2} - 28 x + 102

in the form:

x^{2} + 2 a x + a^{2}

Factor out

2

2 (x^{2} - 14 x + 51)

2 a = - 14 : a = - 7

Add and subtract

(- 7)^{2}

2 (x^{2} - 14 x + 51 + (- 7)^{2} - (- 7)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 14 x + (- 7)^{2} = (x - 7)^{2}

2 ((x - 7)^{2} + 51 - (- 7)^{2})

Simplify

2 (x - 7)^{2} + 4

x, x^{2} + 2 x - 24 = 0

15 x = x^{2} - 16

0 = - \frac{1}{2} (x - 2)^{2} + 8

- 0.000003 x^{2} + 0.003 x + 6 = 0

7 x^{2} + 13 x + 6 = 0

What are the solutions to the equation completesquare 2x^2-28x+102 ?
The solutions to the equation completesquare 2x^2-28x+102 are 2(x-7)^2+4
Find the zeros of completesquare 2x^2-28x+102
The zeros of completesquare 2x^2-28x+102 are 2(x-7)^2+4