What are the solutions to the equation solvefor x,x^2+2x-24=0 ?

The solutions to the equation solvefor x,x^2+2x-24=0 are x=4,x=-6

Find the zeros of solvefor x,x^2+2x-24=0

The zeros of solvefor x,x^2+2x-24=0 are x=4,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, x^{2} + 2 x - 24 = 0

x = 4, x = - 6

Solution steps

x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 1}, x_{2} = \frac{- 2 - 10}{2 \cdot 1}

x = \frac{- 2 + 10}{2 \cdot 1} : 4

x = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 4, x = - 6

15 x = x^{2} - 16

0 = - \frac{1}{2} (x - 2)^{2} + 8

- 0.000003 x^{2} + 0.003 x + 6 = 0

7 x^{2} + 13 x + 6 = 0

2 x^{2} - 11 x + 5 = 0

What are the solutions to the equation solvefor x,x^2+2x-24=0 ?
The solutions to the equation solvefor x,x^2+2x-24=0 are x=4,x=-6
Find the zeros of solvefor x,x^2+2x-24=0
The zeros of solvefor x,x^2+2x-24=0 are x=4,x=-6