What are the solutions to the equation L^2-24L+32=0 ?

The solutions to the equation L^2-24L+32=0 are L=4(3+sqrt(7)),L=4(3-sqrt(7))

Find the zeros of L^2-24L+32=0

The zeros of L^2-24L+32=0 are L=4(3+sqrt(7)),L=4(3-sqrt(7))

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L^{2} - 24 L + 32 = 0

L = 4 (3 + 7), L = 4 (3 - 7)

Decimal Notation

L = 22.58300 \dots, L = 1.41699 \dots

Solution steps

L^{2} - 24 L + 32 = 0

Solve with the quadratic formula

L_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 32 = 87

L_{1, 2} = \frac{- ( - 24 ) \pm 8 7}{2 \cdot 1}

Separate the solutions

L_{1} = \frac{- ( - 24 ) + 8 7}{2 \cdot 1}, L_{2} = \frac{- ( - 24 ) - 8 7}{2 \cdot 1}

L = \frac{- ( - 24 ) + 8 7}{2 \cdot 1} : 4 (3 + 7)

L = \frac{- ( - 24 ) - 8 7}{2 \cdot 1} : 4 (3 - 7)

The solutions to the quadratic equation are:

L = 4 (3 + 7), L = 4 (3 - 7)

28090 = 25000 (1 + x)^{2}

\frac{- t ^{2}}{4} + 400 = 39

(x - 7) (x + 4) = - 2

x, 3 x^{2} + 18 x - 3 y^{2} + 27 = 0

6 0^{2} + x^{2} = 6 1^{2}

What are the solutions to the equation L^2-24L+32=0 ?
The solutions to the equation L^2-24L+32=0 are L=4(3+sqrt(7)),L=4(3-sqrt(7))
Find the zeros of L^2-24L+32=0
The zeros of L^2-24L+32=0 are L=4(3+sqrt(7)),L=4(3-sqrt(7))