What are the solutions to the equation (r-1)(r+1)=0 ?

The solutions to the equation (r-1)(r+1)=0 are r=1,r=-1

Find the zeros of (r-1)(r+1)=0

The zeros of (r-1)(r+1)=0 are r=1,r=-1

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(r - 1) (r + 1) = 0

r = 1, r = - 1

Solution steps

(r - 1) (r + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 1 = 0 or r + 1 = 0

Solve

r - 1 = 0 : r = 1

Solve

r + 1 = 0 : r = - 1

The solutions to the quadratic equation are:

r = 1, r = - 1

x, f x = x^{2} - 4 x

x - x^{2} = 5

0 = 8 x - 4 x^{2}

2 x^{2} + 3 a^{2} = 7 a x

x^{2} - 4 = 0

What are the solutions to the equation (r-1)(r+1)=0 ?
The solutions to the equation (r-1)(r+1)=0 are r=1,r=-1
Find the zeros of (r-1)(r+1)=0
The zeros of (r-1)(r+1)=0 are r=1,r=-1