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Popular >

6u^2-12u=0

Solution

6 u^{2} - 12 u = 0

Solution

u = 2, u = 0

Solution steps

6 u^{2} - 12 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 \cdot 0 = 12

u_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 6}

Separate the solutions

u_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 6}, u_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 6}

u = \frac{- ( - 12 ) + 12}{2 \cdot 6} : 2

u = \frac{- ( - 12 ) - 12}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

u = 2, u = 0

Popular Examples

50x-49/40 x^2=80(x+2)+1/2*(-9.8)(x+2)^2

50 x - \frac{49}{40} x^{2} = 80 (x + 2) + \frac{1}{2} \cdot (- 9.8) (x + 2)^{2}

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(x - 1.2) (x + 1) + 1.44 = 0

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\frac{7 x ^{2} - x}{2} = 168

solvefor v, 1/2 mv^2=gh(m+m)solve for

v, \frac{1}{2} m v^{2} = g h (m + m)

Frequently Asked Questions (FAQ)

What are the solutions to the equation 6u^2-12u=0 ?
The solutions to the equation 6u^2-12u=0 are u=2,u=0
Find the zeros of 6u^2-12u=0
The zeros of 6u^2-12u=0 are u=2,u=0