What are the solutions to the equation c^2+5c+6=0 ?

The solutions to the equation c^2+5c+6=0 are c=-2,c=-3

Find the zeros of c^2+5c+6=0

The zeros of c^2+5c+6=0 are c=-2,c=-3

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c^{2} + 5 c + 6 = 0

c = - 2, c = - 3

Solution steps

c^{2} + 5 c + 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

c_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 5 + 1}{2 \cdot 1}, c_{2} = \frac{- 5 - 1}{2 \cdot 1}

c = \frac{- 5 + 1}{2 \cdot 1} : - 2

c = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

c = - 2, c = - 3

\frac{7 x ^{2} - x}{2} = 168

v, \frac{1}{2} m v^{2} = g h (m + m)

4 u^{2} = - 12 u - 5

a^{2} + 1 7^{2} = 1 9^{2}

25 = a^{2} + 2 a + 10

What are the solutions to the equation c^2+5c+6=0 ?
The solutions to the equation c^2+5c+6=0 are c=-2,c=-3
Find the zeros of c^2+5c+6=0
The zeros of c^2+5c+6=0 are c=-2,c=-3