What is the answer to E=(2^3)^2-(3^2)^3+(5^2)^2 ?

The answer to E=(2^3)^2-(3^2)^3+(5^2)^2 is E=-40

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E=(2^3)^2-(3^2)^3+(5^2)^2

E = (2^{3})^{2} - (3^{2})^{3} + (5^{2})^{2}

E = - 40

Solution steps

E = (2^{3})^{2} - (3^{2})^{3} + (5^{2})^{2}

Simplify

(2^{3})^{2} - (3^{2})^{3} + (5^{2})^{2} : - 40

E = - 40

x, 3 x + y - z = 0

f = 2 + 4

(z - 1)^{2} + 3 = (z + 1)^{2} - 3

2 (x + 1) = (x + 1) + 4

\frac{2 x - 5}{3} - \frac{3 x + 1}{4} = \frac{7 - x}{2}

What is the answer to E=(2^3)^2-(3^2)^3+(5^2)^2 ?
The answer to E=(2^3)^2-(3^2)^3+(5^2)^2 is E=-40
Solve for E: E=(2^3)^2-(3^2)^3+(5^2)^2
The solution is E=-40