What is factor (x+1)^3-64y^3 ?

The solution to factor (x+1)^3-64y^3 is (x+1-4y)((x+1)^2+4y(x+1)+16y^2)

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factor (x+1)^3-64y^3

factor

(x + 1)^{3} - 64 y^{3}

(x + 1 - 4 y) ((x + 1)^{2} + 4 y (x + 1) + 16 y^{2})

Solution steps

(x + 1)^{3} - 64 y^{3}

Rewrite

(x + 1)^{3} - 64 y^{3}

(x + 1)^{3} - (4 y)^{3}

= (x + 1)^{3} - (4 y)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(x + 1)^{3} - (4 y)^{3} = ((x + 1) - 4 y) ((x + 1)^{2} + 4 (x + 1) y + 4^{2} y^{2})

= ((x + 1) - 4 y) ((x + 1)^{2} + 4 y (x + 1) + 4^{2} y^{2})

Refine

= (x + 1 - 4 y) (16 y^{2} + 4 y (x + 1) + (x + 1)^{2})

\frac{1 + 2 i}{3 + 4 i}

15 x^{2} - 3 x = 5 x^{2} - 1

(\frac{5 p}{q ^{2}})^{- 3}

\frac{1}{3 x - 7} \geq \frac{4}{3 - 2 x}

x^{5} y^{3} - x^{2}

What is factor (x+1)^3-64y^3 ?
The solution to factor (x+1)^3-64y^3 is (x+1-4y)((x+1)^2+4y(x+1)+16y^2)