What is (x+1)/(2-x)>= x/(x+3) ?

The solution to (x+1)/(2-x)>= x/(x+3) is -3<x<2

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(x+1)/(2-x)>= x/(x+3)

\frac{x + 1}{2 - x} \geq \frac{x}{x + 3}

- 3 < x < 2

Interval Notation

(- 3, 2)

Solution steps

\frac{x + 1}{2 - x} \geq \frac{x}{x + 3}

Rewrite in standard form

\frac{2 x ^{2} + 2 x + 3}{( - x + 2 ) ( x + 3 )} \geq 0

Identify the intervals

- 3 < x < 2

2 x^{2} + 16 x - 8 = 0

- 6 x^{2} + 6 x - 162 = 0

12 w - 24 = 12

\frac{( 8 c d ^{3} ) ( - 3 c ^{4} )}{6 c ^{2} d} - 9 c^{3} d^{2}

x^{2} y + x^{4} y^{3}