What are the solutions to the equation x^2+11x+3=0 ?

The solutions to the equation x^2+11x+3=0 are x=(-11+sqrt(109))/2 ,x=(-11-sqrt(109))/2

Find the zeros of x^2+11x+3=0

The zeros of x^2+11x+3=0 are x=(-11+sqrt(109))/2 ,x=(-11-sqrt(109))/2

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x^{2} + 11 x + 3 = 0

x = \frac{- 11 + 109}{2}, x = \frac{- 11 - 109}{2}

Decimal Notation

x = - 0.27984 \dots, x = - 10.72015 \dots

Solution steps

x^{2} + 11 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 3 = 109

x_{1, 2} = \frac{- 11 \pm 109}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 109}{2 \cdot 1}, x_{2} = \frac{- 11 - 109}{2 \cdot 1}

x = \frac{- 11 + 109}{2 \cdot 1} : \frac{- 11 + 109}{2}

x = \frac{- 11 - 109}{2 \cdot 1} : \frac{- 11 - 109}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 109}{2}, x = \frac{- 11 - 109}{2}

- 3 i^{2}

p^{2} - 5 p + 4 = 0

x^{2} (x - 4) < 0

r^{2} + 18 r + 81 = 0

- 2 x^{2} - 11 x - 15

What are the solutions to the equation x^2+11x+3=0 ?
The solutions to the equation x^2+11x+3=0 are x=(-11+sqrt(109))/2 ,x=(-11-sqrt(109))/2
Find the zeros of x^2+11x+3=0
The zeros of x^2+11x+3=0 are x=(-11+sqrt(109))/2 ,x=(-11-sqrt(109))/2