What is factor (x+h)^3-(6x+h)+(2+h)-(x^3-6x+2) ?

The solution to factor (x+h)^3-(6x+h)+(2+h)-(x^3-6x+2) is h(h^2+3xh+3x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor (x+h)^3-(6x+h)+(2+h)-(x^3-6x+2)

factor

(x + h)^{3} - (6 x + h) + (2 + h) - (x^{3} - 6 x + 2)

h (h^{2} + 3 x h + 3 x^{2})

Solution steps

(x + h)^{3} - (6 x + h) + (2 + h) - (x^{3} - 6 x + 2)

Remove parentheses:

(a) = a

= (x + h)^{3} - (6 x + h) + 2 + h - (x^{3} - 6 x + 2)

(x + h)^{3} : x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3}

= x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3} - (6 x + h) + 2 + h - (x^{3} - 6 x + 2)

- (6 x + h) : - 6 x - h

= x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3} - 6 x - h + 2 + h - (x^{3} - 6 x + 2)

- (x^{3} - 6 x + 2) : - x^{3} + 6 x - 2

= x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3} - 6 x - h + 2 + h - x^{3} + 6 x - 2

Simplify

x^{3} + 3 x^{2} h + 3 x h^{2} + h^{3} - 6 x - h + 2 + h - x^{3} + 6 x - 2 : h^{3} + 3 x h^{2} + 3 x^{2} h

= h^{3} + 3 x h^{2} + 3 x^{2} h

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

h^{2} x = hh, h^{3} = h h^{2}

= h h^{2} + 3 hh + 3 h x^{2}

Factor out common term

h

= h (h^{2} + 3 h x + 3 x^{2})

p^{2} - 64 = 0

\frac{1}{2} (8 - x) > 6

16 x^{4} - 8 x^{2} y^{2} + y^{4}

(\frac{4}{5})^{2} + y^{2} = 1

- 2 x^{2} > x - 1

What is factor (x+h)^3-(6x+h)+(2+h)-(x^3-6x+2) ?
The solution to factor (x+h)^3-(6x+h)+(2+h)-(x^3-6x+2) is h(h^2+3xh+3x^2)