What is expand (7x+1)(4x-8)2x^2 ?

The solution to expand (7x+1)(4x-8)2x^2 is 56x^4-104x^3-16x^2

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expand (7x+1)(4x-8)2x^2

expand

(7 x + 1) (4 x - 8) 2 x^{2}

56 x^{4} - 104 x^{3} - 16 x^{2}

Solution steps

(7 x + 1) (4 x - 8) \cdot 2 x^{2}

= 2 x^{2} (7 x + 1) (4 x - 8)

Apply FOIL method

(7 x + 1) (4 x - 8) : 28 x^{2} - 52 x - 8

= 2 x^{2} (28 x^{2} - 52 x - 8)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

2 x^{2} (28 x^{2} - 52 x - 8) = 2 x^{2} \cdot 28 x^{2} + 2 x^{2} (- 52 x) + 2 x^{2} (- 8)

= 2 x^{2} \cdot 28 x^{2} + 2 x^{2} (- 52 x) + 2 x^{2} (- 8)

Simplify

2 x^{2} \cdot 28 x^{2} + 2 x^{2} (- 52 x) + 2 x^{2} (- 8) : 56 x^{4} - 104 x^{3} - 16 x^{2}

= 56 x^{4} - 104 x^{3} - 16 x^{2}

\frac{( n - 2 ) !}{( n + 1 ) !}

8 x^{3} + y^{6}

(9 c^{- 9})^{- 3}

a^{- 1} + 1

\frac{9 x ^{2} - 1}{6 x ^{2} + 5 x + 1}

What is expand (7x+1)(4x-8)2x^2 ?
The solution to expand (7x+1)(4x-8)2x^2 is 56x^4-104x^3-16x^2