What is j*(5^{-1}*2^{-1})*6^{-1} ?

The solution to j*(5^{-1}*2^{-1})*6^{-1} is j/(60)

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simplify j(5^{-1}2^{-1})*6^{-1}

simplify

j \cdot (5^{- 1} \cdot 2^{- 1}) \cdot 6^{- 1}

\frac{j}{60}

Solution steps

j (5^{- 1} \cdot 2^{- 1}) \cdot 6^{- 1}

Simplify

5^{- 1} \cdot 2^{- 1} : \frac{1}{10}

= j \frac{1}{10} \cdot 6^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

6^{- 1} = \frac{1}{6}

= j \frac{1}{10} \cdot \frac{1}{6}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{j \cdot 1 \cdot 1}{10 \cdot 6}

Simplify

j \cdot 1 \cdot 1 : j

= \frac{j}{10 \cdot 6}

Multiply the numbers:

10 \cdot 6 = 60

= \frac{j}{60}

\frac{( x ^{3} - 2 x ^{2} + 1 )}{( x - 1 )}

6 x^{3} \cdot y^{2} + 9 x^{2} \cdot y^{3} - 3 x^{2} \cdot y^{2}

\frac{m}{n ( \frac{y}{2} + m + 6 )}

\frac{( n - 2 ) !}{( n - 3 ) !}

\frac{\frac{3}{x}}{\frac{1}{2}}

What is j*(5^{-1}*2^{-1})*6^{-1} ?
The solution to j*(5^{-1}*2^{-1})*6^{-1} is j/(60)