What is ((9k^2-33k+10))/((18k^3-200k)) ?

The solution to ((9k^2-33k+10))/((18k^3-200k)) is (3k-1)/(2k(3k+10))

Popular >

simplify ((9k^2-33k+10))/((18k^3-200k))

simplify

\frac{( 9 k ^{2} - 33 k + 10 )}{( 18 k ^{3} - 200 k )}

\frac{3 k - 1}{2 k ( 3 k + 10 )}

Solution steps

\frac{9 k ^{2} - 33 k + 10}{18 k ^{3} - 200 k}

Factor

9 k^{2} - 33 k + 10 : (3 k - 1) (3 k - 10)

= \frac{( 3 k - 1 ) ( 3 k - 10 )}{18 k ^{3} - 200 k}

Factor

18 k^{3} - 200 k : 2 k (3 k + 10) (3 k - 10)

= \frac{( 3 k - 1 ) ( 3 k - 10 )}{2 k ( 3 k + 10 ) ( 3 k - 10 )}

Cancel the common factor:

3 k - 10

= \frac{3 k - 1}{2 k ( 3 k + 10 )}

\frac{( x ^{3} - 4 x ^{2} + x + 6 )}{( x ^{2} - 2 x - 3 )}

(x + 2 y) (x + 2 y + 4) - 12

50 x^{2} + 18 y^{2}

\frac{( 3 x ^{2} + 16 x + 5 )}{( 9 x ^{2} - 1 )}

(2 n + 1)^{5}

What is ((9k^2-33k+10))/((18k^3-200k)) ?
The solution to ((9k^2-33k+10))/((18k^3-200k)) is (3k-1)/(2k(3k+10))