What is (((x^{-4}))/((4y^6)))^{1/2} ?

The solution to (((x^{-4}))/((4y^6)))^{1/2} is 1/(2x^2y^3)

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simplify (((x^{-4}))/((4y^6)))^{1/2}

simplify

(\frac{( x ^{- 4} )}{( 4 y ^{6} )})^{\frac{1}{2}}

\frac{1}{2 x ^{2} y ^{3}}

Solution steps

(\frac{x ^{- 4}}{4 y ^{6}})^{\frac{1}{2}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{- 4} ) ^{\frac{1}{2}}}{( 4 y ^{6} ) ^{\frac{1}{2}}}

Simplify

(x^{- 4})^{\frac{1}{2}} : \frac{1}{x ^{2}}

= \frac{\frac{1}{x ^{2}}}{( 4 y ^{6} ) ^{\frac{1}{2}}}

Simplify

(4 y^{6})^{\frac{1}{2}} : 2 y^{3}

= \frac{\frac{1}{x ^{2}}}{2 y ^{3}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{1}{2 x ^{2} y ^{3}}

2 x^{2} (\frac{2 - 3}{x ^{2}})^{2}

p (p - 1) (p - 2) (p - 3) (p - 4) (p - 5)

(\frac{2 x ^{2} + 5}{3 y})^{2}

[(a^{- 1})]^{- 1}

15 + x (7 - 2 x)

What is (((x^{-4}))/((4y^6)))^{1/2} ?
The solution to (((x^{-4}))/((4y^6)))^{1/2} is 1/(2x^2y^3)