What is the answer to (x+3)(x+2)(x-1)=(x-4)(x+4)(x+4)+7 ?

The answer to (x+3)(x+2)(x-1)=(x-4)(x+4)(x+4)+7 is x=-3

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(x+3)(x+2)(x-1)=(x-4)(x+4)(x+4)+7

(x + 3) (x + 2) (x - 1) = (x - 4) (x + 4) (x + 4) + 7

x = - 3

Solution steps

(x + 3) (x + 2) (x - 1) = (x - 4) (x + 4) (x + 4) + 7

Simplify

(x - 4) (x + 4) (x + 4) + 7 : (x - 4) (x + 4)^{2} + 7

(x + 3) (x + 2) (x - 1) = (x - 4) (x + 4)^{2} + 7

Expand

(x + 3) (x + 2) : x^{2} + 5 x + 6

(x^{2} + 5 x + 6) (x - 1) = (x - 4) (x + 4)^{2} + 7

Expand

(x^{2} + 5 x + 6) (x - 1) : x^{3} + 4 x^{2} + x - 6

x^{3} + 4 x^{2} + x - 6 = (x - 4) (x + 4)^{2} + 7

Expand

(x - 4) (x + 4)^{2} + 7 : x^{3} + 4 x^{2} - 16 x - 57

x^{3} + 4 x^{2} + x - 6 = x^{3} + 4 x^{2} - 16 x - 57

Move

6

to the right side

x^{3} + 4 x^{2} + x = x^{3} + 4 x^{2} - 16 x - 51

Subtract

x^{3} + 4 x^{2} - 16 x

from both sides

x^{3} + 4 x^{2} + x - (x^{3} + 4 x^{2} - 16 x) = x^{3} + 4 x^{2} - 16 x - 51 - (x^{3} + 4 x^{2} - 16 x)

Simplify

17 x = - 51

Divide both sides by

17

x = - 3

x, 3 x + 6 y = 30

x, 2 x + 3 y - z = 15

\frac{x}{2} + \frac{2}{3} = \frac{x}{3} + 1 - \frac{1}{2} \cdot (1 - \frac{( x + 1 )}{3})

z, f = 3!

(5 x - 1)^{2} - 7 x (3 x - 2) = (2 x - 3)^{2}

What is the answer to (x+3)(x+2)(x-1)=(x-4)(x+4)(x+4)+7 ?
The answer to (x+3)(x+2)(x-1)=(x-4)(x+4)(x+4)+7 is x=-3
Solve for x: (x+3)(x+2)(x-1)=(x-4)(x+4)(x+4)+7
The solution is x=-3