What is the answer to solvefor x,(-x)p+(2x)q=x-y ?

The answer to solvefor x,(-x)p+(2x)q=x-y is x=-y/(-p+2q-1);\quad p\ne 2q-1

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solvefor x,(-x)p+(2x)q=x-y

solve for

x, (- x) p + (2 x) q = x - y

x = - \frac{y}{- p + 2 q - 1}; p \neq = 2 q - 1

Solution steps

(- x) p + (2 x) q = x - y

- p x + 2 x q = x - y

Move

x

to the left side

- p x + 2 x q - x = - y

Factor

- p x + 2 x q - x : x (- p + 2 q - 1)

x (- p + 2 q - 1) = - y

Divide both sides by

- p + 2 q - 1; p \neq = 2 q - 1

x = - \frac{y}{- p + 2 q - 1}; p \neq = 2 q - 1

x, \frac{x}{y} = - 1

x, 4 x + 5 y = 24

\frac{( 10 x )}{11} - \frac{( 3 x )}{2} = 33 x - \frac{x}{2} + 7

n, n (x) = 2 x^{2} + 4 - 6 x - 2 x^{3} + x^{2} + 1

f, - f \cdot (x) = (4 - x)^{3}

What is the answer to solvefor x,(-x)p+(2x)q=x-y ?
The answer to solvefor x,(-x)p+(2x)q=x-y is x=-y/(-p+2q-1);\quad p\ne 2q-1