What is factor x^2-40x+400 ?

The solution to factor x^2-40x+400 is (x-20)^2

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factor x^2-40x+400

factor

x^{2} - 40 x + 400

(x - 20)^{2}

Solution steps

x^{2} - 40 x + 400

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

400 = 2 0^{2}

- 40 x = - 2 x \cdot 20

= x^{2} - 2 x \cdot 20 + 2 0^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

x^{2} - 2 x \cdot 20 + 2 0^{2} = (x - 20)^{2}

= (x - 20)^{2}

lo g_{0.2} (x^{2} + 1) \leq lo g_{0.2} (x^{2} + x + 3)

- \frac{2}{3} x^{2} - 1 = 17

s^{2} - 5 s + 4 = 0

18 y^{3} - 50 y

\frac{3 x + 6}{x ( x - 4 )} \leq 0