What is (m^{5/3}n^{-2/5})^{6/7} ?

The solution to (m^{5/3}n^{-2/5})^{6/7} is (m^{10/7})/(n^{12/35)}

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simplify (m^{5/3}n^{-2/5})^{6/7}

simplify

(m^{\frac{5}{3}} n^{- \frac{2}{5}})^{\frac{6}{7}}

\frac{m ^{\frac{10}{7}}}{n ^{\frac{12}{35}}}

Solution steps

(m^{\frac{5}{3}} n^{- \frac{2}{5}})^{\frac{6}{7}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(m^{\frac{5}{3}} n^{- \frac{2}{5}})^{\frac{6}{7}} = (m^{\frac{5}{3}})^{\frac{6}{7}} (n^{- \frac{2}{5}})^{\frac{6}{7}}

= (m^{\frac{5}{3}})^{\frac{6}{7}} (n^{- \frac{2}{5}})^{\frac{6}{7}}

Simplify

(m^{\frac{5}{3}})^{\frac{6}{7}} : m^{\frac{10}{7}}

= m^{\frac{10}{7}} (n^{- \frac{2}{5}})^{\frac{6}{7}}

Simplify

(n^{- \frac{2}{5}})^{\frac{6}{7}} : \frac{1}{n ^{\frac{12}{35}}}

= m^{\frac{10}{7}} \frac{1}{n ^{\frac{12}{35}}}

Simplify

m^{\frac{10}{7}} \frac{1}{n ^{\frac{12}{35}}} : \frac{m ^{\frac{10}{7}}}{n ^{\frac{12}{35}}}

= \frac{m ^{\frac{10}{7}}}{n ^{\frac{12}{35}}}

\frac{2}{3} h > 14

8 b - 4 \geq 3 (b + 3) + 5 b

28 p^{2} \frac{q ^{4}}{\frac{4 p q ^{4}}{5 r}}

3^{n + 1} + 3^{n} - 12 \cdot 3^{n - 1}

9 (x + 10) = - 63

What is (m^{5/3}n^{-2/5})^{6/7} ?
The solution to (m^{5/3}n^{-2/5})^{6/7} is (m^{10/7})/(n^{12/35)}