What is the answer to 1((2x+3))/3+((3x-8))/4 = 15/6 ?

The answer to 1((2x+3))/3+((3x-8))/4 = 15/6 is x= 42/17

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1((2x+3))/3+((3x-8))/4 = 15/6

1 \frac{( 2 x + 3 )}{3} + \frac{( 3 x - 8 )}{4} = \frac{15}{6}

x = \frac{42}{17}

Decimal Notation

x = 2.47058 \dots

Solution steps

1 \cdot \frac{( 2 x + 3 )}{3} + \frac{( 3 x - 8 )}{4} = \frac{15}{6}

Expand

1 \cdot \frac{2 x + 3}{3} + \frac{3 x - 8}{4} : \frac{17 x}{12} - 1

Expand

\frac{15}{6} : \frac{5}{2}

\frac{17 x}{12} - 1 = \frac{5}{2}

Multiply both sides by

12

17 x - 12 = 30

Move

12

to the right side

17 x = 42

Divide both sides by

17

x = \frac{42}{17}

x, 3 x + 4 y = 300

v (12) = 15000 e - 1.8

d = (\frac{3}{4 - 0})^{2} + (0 - 4)^{2}

r = 8^{2} + 6^{2} + 2 (8) (1)

x, sin (y) = 1 - tan (x)

What is the answer to 1((2x+3))/3+((3x-8))/4 = 15/6 ?
The answer to 1((2x+3))/3+((3x-8))/4 = 15/6 is x= 42/17
Solve for x: 1((2x+3))/3+((3x-8))/4 = 15/6
The solution is x= 42/17