What are the solutions to the equation 9x^2-4x-2=0 ?

The solutions to the equation 9x^2-4x-2=0 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9

Find the zeros of 9x^2-4x-2=0

The zeros of 9x^2-4x-2=0 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9

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9 x^{2} - 4 x - 2 = 0

x = \frac{2 + 22}{9}, x = \frac{2 - 22}{9}

Decimal Notation

x = 0.74337 \dots, x = - 0.29893 \dots

Solution steps

9 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

(- 4)^{2} - 4 \cdot 9 (- 2) = 222

x_{1, 2} = \frac{- ( - 4 ) \pm 2 22}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 22}{2 \cdot 9}, x_{2} = \frac{- ( - 4 ) - 2 22}{2 \cdot 9}

x = \frac{- ( - 4 ) + 2 22}{2 \cdot 9} : \frac{2 + 22}{9}

x = \frac{- ( - 4 ) - 2 22}{2 \cdot 9} : \frac{2 - 22}{9}

The solutions to the quadratic equation are:

x = \frac{2 + 22}{9}, x = \frac{2 - 22}{9}

4 + x - 4 (1 - x) + 5 (2 + x) = 0

4 x (3 x - 7) = 5

\frac{w ^{2}}{8} - \frac{w}{2} - 4 = 0

196 - x^{2}

- \frac{10}{3} - 1

What are the solutions to the equation 9x^2-4x-2=0 ?
The solutions to the equation 9x^2-4x-2=0 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9
Find the zeros of 9x^2-4x-2=0
The zeros of 9x^2-4x-2=0 are x=(2+sqrt(22))/9 ,x=(2-sqrt(22))/9