What is the answer to solvefor z,minz=3a+2b ?

The answer to solvefor z,minz=3a+2b is z=i(-2b-3a)/(mn);\quad m\ne 0

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solvefor z,minz=3a+2b

solve for

z, min z = 3 a + 2 b

z = i \frac{- 2 b - 3 a}{mn}; m \neq = 0

Solution steps

min z = 3 a + 2 b

Divide both sides by

min; m \neq = 0

z = i \frac{- 2 b - 3 a}{mn}; m \neq = 0

(2 x - 5) (2 x + 5) - (2 x + 1)^{2} = 4

x, 3 x - 4 y = - 23

3 (x + 21) = 81

a, f = \frac{a}{b} - 3 c

\frac{x}{2} - 4 = 8, x

What is the answer to solvefor z,minz=3a+2b ?
The answer to solvefor z,minz=3a+2b is z=i(-2b-3a)/(mn);\quad m\ne 0