What are the solutions to the equation -x^2+5x=2 ?

The solutions to the equation -x^2+5x=2 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2

Find the zeros of -x^2+5x=2

The zeros of -x^2+5x=2 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2

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- x^{2} + 5 x = 2

x = \frac{5 - 17}{2}, x = \frac{5 + 17}{2}

Solution steps

- x^{2} + 5 x = 2

Move

2

to the left side

- x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 2) = 17

x_{1, 2} = \frac{- 5 \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 17}{2 ( - 1 )}, x_{2} = \frac{- 5 - 17}{2 ( - 1 )}

x = \frac{- 5 + 17}{2 ( - 1 )} : \frac{5 - 17}{2}

x = \frac{- 5 - 17}{2 ( - 1 )} : \frac{5 + 17}{2}

The solutions to the quadratic equation are:

x = \frac{5 - 17}{2}, x = \frac{5 + 17}{2}

- 9 x^{2} - 12 x - 4 = 0

17 w - 1 > - 18

2 w^{2} - 3 w - 65 = 0

∣ x - 2 ∣ + 2 < 3

\frac{x ^{2 n + 1}}{x ^{2 n - 1}}

What are the solutions to the equation -x^2+5x=2 ?
The solutions to the equation -x^2+5x=2 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2
Find the zeros of -x^2+5x=2
The zeros of -x^2+5x=2 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2