What are the solutions to the equation 3x^3-2x^2-7x=2 ?

The solutions to the equation 3x^3-2x^2-7x=2 are x=-1,x=-1/3 ,x=2

Find the zeros of 3x^3-2x^2-7x=2

The zeros of 3x^3-2x^2-7x=2 are x=-1,x=-1/3 ,x=2

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3 x^{3} - 2 x^{2} - 7 x = 2

x = - 1, x = - \frac{1}{3}, x = 2

Decimal Notation

x = - 1, x = - 0.33333 \dots, x = 2

Solution steps

3 x^{3} - 2 x^{2} - 7 x = 2

Move

2

to the left side

3 x^{3} - 2 x^{2} - 7 x - 2 = 0

Factor

3 x^{3} - 2 x^{2} - 7 x - 2 : (x + 1) (3 x + 1) (x - 2)

(x + 1) (3 x + 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = - \frac{1}{3}, x = 2

x^{4} + 2 x^{2} + 4 = 0

5 y^{3} + 17 y - 12 = 9 y^{2} - 9 y

4 x + 3 = x^{3} + 3 x^{2} - 9 x - 12

x^{3} - x^{2} - 5 x - 3 = 0

5 x^{3} + 23 x^{2} + 20 x - 12 = 0

What are the solutions to the equation 3x^3-2x^2-7x=2 ?
The solutions to the equation 3x^3-2x^2-7x=2 are x=-1,x=-1/3 ,x=2
Find the zeros of 3x^3-2x^2-7x=2
The zeros of 3x^3-2x^2-7x=2 are x=-1,x=-1/3 ,x=2