What are the solutions to the equation x^3+2x^2+3x-22=0 ?

The solutions to the equation x^3+2x^2+3x-22=0 are x=2,x=-2+sqrt(7)i,x=-2-sqrt(7)i

Find the zeros of x^3+2x^2+3x-22=0

The zeros of x^3+2x^2+3x-22=0 are x=2,x=-2+sqrt(7)i,x=-2-sqrt(7)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + 2 x^{2} + 3 x - 22 = 0

x = 2, x = - 2 + 7 i, x = - 2 - 7 i

Solution steps

x^{3} + 2 x^{2} + 3 x - 22 = 0

Factor

x^{3} + 2 x^{2} + 3 x - 22 : (x - 2) (x^{2} + 4 x + 11)

(x - 2) (x^{2} + 4 x + 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 4 x + 11 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 4 x + 11 = 0 : x = - 2 + 7 i, x = - 2 - 7 i

The solutions are

x = 2, x = - 2 + 7 i, x = - 2 - 7 i

m^{3} + m = 0

6 c^{2} + 20 c - 25 - c^{3} = 0

r^{4} = 4

43 - 2 (x + 3)^{4} = 11

(x + 11)^{4} = 169

What are the solutions to the equation x^3+2x^2+3x-22=0 ?
The solutions to the equation x^3+2x^2+3x-22=0 are x=2,x=-2+sqrt(7)i,x=-2-sqrt(7)i
Find the zeros of x^3+2x^2+3x-22=0
The zeros of x^3+2x^2+3x-22=0 are x=2,x=-2+sqrt(7)i,x=-2-sqrt(7)i