What are the solutions to the equation s^4+4s^3+6s^2+4s+1=0 ?

The solutions to the equation s^4+4s^3+6s^2+4s+1=0 are s=-1

Find the zeros of s^4+4s^3+6s^2+4s+1=0

The zeros of s^4+4s^3+6s^2+4s+1=0 are s=-1

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s^{4} + 4 s^{3} + 6 s^{2} + 4 s + 1 = 0

s = - 1

Solution steps

s^{4} + 4 s^{3} + 6 s^{2} + 4 s + 1 = 0

Factor

s^{4} + 4 s^{3} + 6 s^{2} + 4 s + 1 : (s + 1)^{4}

(s + 1)^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 1 = 0

Solve

s + 1 = 0 : s = - 1

The solution is

s = - 1

x^{3} - 4 x + 1 = 0

x^{1000} = 0.9

x^{3} - 3 x^{2} - 10 x + 24 = 0

(x^{2} + 1) (1 - 7 x) = 0

x^{4} - 4 x^{3} - 4 x^{2} - 10 = 0

What are the solutions to the equation s^4+4s^3+6s^2+4s+1=0 ?
The solutions to the equation s^4+4s^3+6s^2+4s+1=0 are s=-1
Find the zeros of s^4+4s^3+6s^2+4s+1=0
The zeros of s^4+4s^3+6s^2+4s+1=0 are s=-1