What are the solutions to the equation x^3-3x^2-10x+24=0 ?

The solutions to the equation x^3-3x^2-10x+24=0 are x=2,x=-3,x=4

Find the zeros of x^3-3x^2-10x+24=0

The zeros of x^3-3x^2-10x+24=0 are x=2,x=-3,x=4

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x^{3} - 3 x^{2} - 10 x + 24 = 0

x = 2, x = - 3, x = 4

Solution steps

x^{3} - 3 x^{2} - 10 x + 24 = 0

Factor

x^{3} - 3 x^{2} - 10 x + 24 : (x - 2) (x + 3) (x - 4)

(x - 2) (x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = 2, x = - 3, x = 4

(x^{2} + 1) (1 - 7 x) = 0

x^{4} - 4 x^{3} - 4 x^{2} - 10 = 0

x^{4} - 8 x^{2} + x + 12 = 0

z^{3} + z^{2} + z + 1 = 0

(2 x - 1)^{4} - 16 = 0

What are the solutions to the equation x^3-3x^2-10x+24=0 ?
The solutions to the equation x^3-3x^2-10x+24=0 are x=2,x=-3,x=4
Find the zeros of x^3-3x^2-10x+24=0
The zeros of x^3-3x^2-10x+24=0 are x=2,x=-3,x=4