What are the solutions to the equation 5(x^2+x-12)(x-8)=0 ?

The solutions to the equation 5(x^2+x-12)(x-8)=0 are x=3,x=-4,x=8

Find the zeros of 5(x^2+x-12)(x-8)=0

The zeros of 5(x^2+x-12)(x-8)=0 are x=3,x=-4,x=8

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5 (x^{2} + x - 12) (x - 8) = 0

x = 3, x = - 4, x = 8

Solution steps

5 (x^{2} + x - 12) (x - 8) = 0

Factor

5 (x^{2} + x - 12) (x - 8) : 5 (x - 3) (x + 4) (x - 8)

5 (x - 3) (x + 4) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 4 = 0 or x - 8 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

Solve

x - 8 = 0 : x = 8

The solutions are

x = 3, x = - 4, x = 8

k^{4} + 2 k^{3} - 3 k^{2} - 6 k + 1 = 0

x^{4} - (5 + 2) x^{2} + 10 = 0

(x - 3)^{3} = 2 x (x^{2} - 1)

2 x^{3} - 9 x^{2} + 13 x - 6 = 0

2 x^{3} + 6 x^{2} - x - 3 = 0

What are the solutions to the equation 5(x^2+x-12)(x-8)=0 ?
The solutions to the equation 5(x^2+x-12)(x-8)=0 are x=3,x=-4,x=8
Find the zeros of 5(x^2+x-12)(x-8)=0
The zeros of 5(x^2+x-12)(x-8)=0 are x=3,x=-4,x=8