What are the solutions to the equation 2x^3-9x^2+13x-6=0 ?

The solutions to the equation 2x^3-9x^2+13x-6=0 are x=1,x= 3/2 ,x=2

Find the zeros of 2x^3-9x^2+13x-6=0

The zeros of 2x^3-9x^2+13x-6=0 are x=1,x= 3/2 ,x=2

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2 x^{3} - 9 x^{2} + 13 x - 6 = 0

x = 1, x = \frac{3}{2}, x = 2

Decimal Notation

x = 1, x = 1.5, x = 2

Solution steps

2 x^{3} - 9 x^{2} + 13 x - 6 = 0

Factor

2 x^{3} - 9 x^{2} + 13 x - 6 : (x - 1) (2 x - 3) (x - 2)

(x - 1) (2 x - 3) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x - 3 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = \frac{3}{2}, x = 2

2 x^{3} + 6 x^{2} - x - 3 = 0

1 - (p + 3)^{3} = - 8

(4^{2} - x)^{4} = 16

2 = (\frac{1 + r}{100})^{6}

2 x^{4} - x^{3} - 3 x^{2} - 9 x - 4 = 0

What are the solutions to the equation 2x^3-9x^2+13x-6=0 ?
The solutions to the equation 2x^3-9x^2+13x-6=0 are x=1,x= 3/2 ,x=2
Find the zeros of 2x^3-9x^2+13x-6=0
The zeros of 2x^3-9x^2+13x-6=0 are x=1,x= 3/2 ,x=2