What are the solutions to the equation 2x^{24}x-16=2 ?

The solutions to the equation 2x^{24}x-16=2 are x=\sqrt[25]{9}

Find the zeros of 2x^{24}x-16=2

The zeros of 2x^{24}x-16=2 are x=\sqrt[25]{9}

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2 x^{24} x - 16 = 2

Decimal Notation

x = 1.09186 \dots

Solution steps

2 x^{24} x - 16 = 2

Move

16

to the right side

2 x^{24} x = 18

Simplify

2 x^{25} = 18

Divide both sides by

2

\frac{2 x ^{25}}{2} = \frac{18}{2}

x^{25} = 9

For

x^{n} = f (a)

, n is odd, the solution is

25 = 15 (1 + r)^{5}

x^{5} - 5 x^{3} + 4 x = 0

t^{3} - 6 t^{2} + 6 = 0

x^{3} + 3 x^{2} + 3 x + 18 = 0

x^{6} + 28 x^{3} + 16 = 0

What are the solutions to the equation 2x^{24}x-16=2 ?
The solutions to the equation 2x^{24}x-16=2 are x=\sqrt[25]{9}
Find the zeros of 2x^{24}x-16=2
The zeros of 2x^{24}x-16=2 are x=\sqrt[25]{9}