What are the solutions to the equation solvefor p,z=p^2+q^2 ?

The solutions to the equation solvefor p,z=p^2+q^2 are p=sqrt(z-q^2),p=-sqrt(z-q^2)

Find the zeros of solvefor p,z=p^2+q^2

The zeros of solvefor p,z=p^2+q^2 are p=sqrt(z-q^2),p=-sqrt(z-q^2)

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solve for

p, z = p^{2} + q^{2}

p = z - q^{2}, p = - z - q^{2}

Solution steps

z = p^{2} + q^{2}

Switch sides

p^{2} + q^{2} = z

Move

q^{2}

to the right side

p^{2} = z - q^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = z - q^{2}, p = - z - q^{2}

x, f 1^{\cdot} (x) = x^{2} - 2 x - 8

32 \cdot x^{2} - 5 x - 2 = 0

63 \cdot x^{2} + 7 x = 3

n, p = (n^{2}) + 1

(\frac{x + 1}{3}) (\frac{x - 1}{3}) = \frac{1}{3}

What are the solutions to the equation solvefor p,z=p^2+q^2 ?
The solutions to the equation solvefor p,z=p^2+q^2 are p=sqrt(z-q^2),p=-sqrt(z-q^2)
Find the zeros of solvefor p,z=p^2+q^2
The zeros of solvefor p,z=p^2+q^2 are p=sqrt(z-q^2),p=-sqrt(z-q^2)